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00:00 - 00:59 | the question is find the sum of the following arithmetic progression automatic progression that is 40 13631 up to 12 atoms have to try it inside Navya Residency there is an ap whose first term at is 41 that a present for storm by a = 241 right and that is common difference which equals to the difference between successive terms with the rest of the 36 - 45 where d is equal to E27 you can say it or you can say is -2 which is equal to 36 - 41 let me -5 so here we get the first term is 41 and common difference is -5 right now and it is as given in shop in the question that we have to find the sum of the items that means we can see our n is equal to 12 right now we know that some of |

01:00 - 01:59 | sum of n terms sum of n terms in an ap is equal to 1 by 2 into 2 plus and minus 1 into this question we have to find the sum of two terms Pyar to find us when we have to find 12 right so as 12 is equals to 1 by 2 that means 12 by 2 into 2 way that means to in 241 where is equal to 41 plus and minus 12 - 111 into DB Aadi is equals to minus of 5 right now that's all so here we have as 12 is equals to how to get 9641 it true that means 82 - 55 right now let's all father so here we have 62275 the sequel to 162 and frequency that the sum of 12 ton |

02:00 - 02:59 | is equal to 162 and is a final answer that of 12 town of that given APS 162 thank you |